The coordinates of the
vertices of quadrilateral ABCD are:

A(-4,-3), B(4,2), C(2,-2),
and D(6,-5).

What is the area of quadrilateral
ABCD?

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A
solution to this problem will appear along with
next month’s problem.

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March's
Problem

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The average (mean) of three
numbers is 5/6. Two of the three numbers are 1/2 and 2/3.
What is the third number in lowest terms?

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METHOD
1: Find the sum of the three. Since the average of the three numbers is their
sum divided by 3, their sum is 3 times their average.
Thus, the sum of the three numbers is 5/6 x 3 =
15/6. Then 1/2 + 2/3 + the third number is equal
to 15/6. The third number is 15/6 - 1/2 - 2/3 =
4/3 or 1 1/3.

METHOD
2: Find Use Algebra.
5/6 = 1/3( 1/2 + 2/3 + x) [Distribute 1/3 to each
term in the parentheses.]
5/6 = 1/6 + 2/9 + x/3 [Combine number terms.]
15/18 = 7/18 + x/3 [Combine.]
8/18 = x/3 [Multiply both sides by 3.]
24/18 = x So x = 4/3.

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February's
Problem

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A large cube 2 meters along
each edge is cut into small cubes that are 2 centimeters
along each edge. How many small cubes are there?

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METHOD:
Determine the number of cubes on an edge 2 m = 100 × 2 cm. So there are 100 small
cubes along each edge. Since a cube is three dimensional,
the large cube is cut into 100 × 100 ×
100 = 1,000,000 small cubes.

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